Python Program for Removing i-th Character from a String

Last Updated : 12 Nov, 2025

Given a string and an index i, remove the character at the i-th position and return the resulting string. For Example:

Input: "PythonProgramming", i = 6
Output: "Pythonrogramming"

Let's explore different methods to do this task.

Using String Slicing

This method removes the i-th character by directly taking parts of the string before and after the character and joining them together. It is fast and memory-efficient.

Python 
s = "PythonProgramming"
i = 6
res = s[:i] + s[i+1:]
print(res)

Output
Pythonrogramming

Explanation:

  • s[:i]: Extracts characters from the start up to (but not including) index i.
  • s[i+1:]: Extracts characters from index i+1 to the end.
  • '+': Concatenates the two slices, skipping the i-th character.

Using join() with List Comprehension

This method creates a new string by iterating over all characters and joining only those that are not at the i-th index.

Python 
s = "PythonProgramming"
i = 6
res = ''.join([s[j] for j in range(len(s)) if j != i])
print(res)

Output
Pythonrogramming

Explanation:

  • [s[j] for j in range(len(s)) if j != i]: Iterates through all indices and skips the i-th character.
  • ''.join(...): Converts the list of characters back into a string.

Using replace() with Slicing

This method removes the i-th character by replacing its first occurrence with an empty string.

Python 
s = "PythonProgramming"
i = 6
res = s[:i] + s[i:].replace(s[i], '', 1)
print(res)

Output
Pythonrogramming

Explanation: s[:i] + s[i:].replace(s[i], '', 1): Removes the i-th character by joining the part before i with the remaining substring after deleting s[i].

Using a For Loop

The for loop iterates over each character in the string and adds it to a new string only if it is not at the i-th position.

Python 
s = "PythonProgramming"
i = 6

res = ''
for j in range(len(s)):
    if j != i:
        res += s[j]
print(res)

Output
Pythonrogramming

Explanation:

  • for j in range(len(s)) with if j != i: Loop through all indices, skipping the i-th.
  • res += s[j]: Concatenate characters to res one by one.
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